
How is this possible ?
The sum of the numbers form the last two digits and the difference between the numbers form the first digit.

| The 3 digit numbers 407 and 370 have this peculiarity, that they exactly equal the sum of the cubes of their digits. Thus the cube of 4 is 64, the cube of 0 is 0, and the cube of7 is 343. Add together 64, 0, and 343, and you get 407. Again, the cube of 3 (27), added to the cube of 7 (343), is 370. Can you find a number not containing a zero that will work in the same way? |
(bp-1 - 1) / p
Example:
Number = 142857,
142857 × 1 = 142857
142857 × 2 = 285714
142857 × 3 = 428571
142857 × 4 = 571428
142857 × 5 = 714285
142857 × 6 = 857142
Thanks,
easycalculation.com
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Sum (or difference) of 2 reals equals a real numberAdditive Identity
a + 0 = aAdditive Inverse
a + (-a) = 0Associative of Addition
(a + b) + c = a + (b + c)Commutative of Addition
a + b = b + aDefinition of Subtraction
a - b = a + (-b)

Product (or quotient if denominatorMultiplicative Identity0) of 2 reals equals a real number
a * 1 = aMultiplicative Inverse
a * (1/a) = 1 (a(Multiplication times 0)0)
a * 0 = 0Associative of Multiplication
(a * b) * c = a * (b * c)Commutative of Multiplication
a * b = b * aDistributive Law
a(b + c) = ab + acDefinition of Division
a / b = a(1/b)